If an objects vbr is 6.32N/sc what is its mass? I'm so stuck...:((((
Solve:
vbr{lr<5vvx><f(nn)/.bbn>
vbr<lr><5.12>(9.8)^3
.bbn=%ff
%ff=F(9x)
.bbn=%ff9x
.bbn=.133%tri
.bbn=.tri
t.ri=vbr
v=161.2
b=39.1
r=12.7
mass=.66kg
Remember the .bbn is equal to the percent factor of the function by 9x or inversely with y9.
Thank you!!! Why is t.ri = vbr and not just tri?
Factor out .bbn and vbr and solve with tri the decimal place is moved one.
To find the mass of an object given its velocity-based resistance (VBR), you need to use Newton's second law of motion. The formula for calculating force is:
Force (F) = mass (m) x acceleration (a)
In this case, the VBR is given in Newtons per second squared (N/s^2), which represents the acceleration. Rearranging the formula, we have:
F = m x a
Given that the VBR is 6.32 N/s and the acceleration is expressed in N/s^2, we can substitute these values into the equation:
6.32 N/s^2 = m x a
Now, to isolate the mass (m), divide both sides of the equation by the acceleration (a):
m = 6.32 N/s^2 / a
Since the acceleration is represented by VBR, we can substitute it into the equation:
m = 6.32 N/s^2 / VBR
By plugging in the value of VBR (6.32 N/s^2), you can solve for the mass of the object.