if a 65 inch of wire is divided into 7 equal pieces how much wire is left over?
For those who are having trouble, I divide 65 and 7. what the remainder is, is the answer to the question
To find out how much wire is left over when a 65-inch wire is divided into 7 equal pieces, we need to divide the total length of the wire by the number of pieces.
To do this, we can use division.
65 divided by 7 = 9.2857 (rounded to 4 decimal places)
So, each piece of the wire would be approximately 9.2857 inches long.
Now, to calculate how much wire is left over, we need to find the remainder of the division.
To do this, we subtract the length of one piece (9.2857 inches) multiplied by the number of pieces (7) from the total length of the wire (65 inches).
65 inches - (9.2857 inches * 7 pieces) = 65 inches - 65 inches = 0 inches
Therefore, there is no wire left over when dividing a 65-inch wire into 7 equal pieces.
65/7= what?
than have a remainder of what?