physics 209

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A mass m = 0.5 kg is hung from a pulley with moment of inertia I = 0.20kg⋅m2 and radius R = 10cm. There is friction in the pulley. The mass is dropped from rest, and after 2s it traveled 0.4m. What is the torque due to friction?

  • physics 209 -

    s=at²/2 => a=2s/t²=2•0.4/2²=0.2 m/s²
    The equation of the load motion
    ma=mg-T => T=m(g-a)
    The equation of the pulley motion
    Iε=M-M(fr)
    M(fr) = M-Iε = TR-Ia/R=
    =m(g-a)R – Ia/R = ...

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