In this lab experiment you will make 100.0 mL of a 0.100 M solution of Co(NO3)2. However you must calculate the number of moles of compound that will be needed (moles= Molarity x Liters).Then calculate the mass of Co(NO3)2 that will need to be weighed out (mass= moles x molar mass)
CAN SOMEONE PLEASE EXPLAIN TO ME HOW TO DO THIS??
I shall be happy to help if you explain what your problems are. The question clearly tells you, at least in my opinion, exactly what to do.
thanks! But it turns out I was over thinking it!
To calculate the number of moles of Co(NO3)2 needed, you need to use the formula:
moles = molarity x volume
Given:
Molarity (M) = 0.100 M
Volume (L) = 100.0 mL = 0.100 L
Substituting the given values into the formula, we get:
moles = 0.100 M x 0.100 L
Now, to calculate the mass of Co(NO3)2 that needs to be weighed out, you need to use the formula:
mass = moles x molar mass
First, you need to find the molar mass of Co(NO3)2 by summing the atomic masses of its constituent elements:
Molar mass (Co(NO3)2) = atomic mass (Co) + 2 x atomic mass (N) + 6 x atomic mass (O)
The atomic masses can be found on the periodic table. Let's assume the atomic mass of Co (cobalt) is 58.93 g/mol, N (nitrogen) is 14.01 g/mol, and O (oxygen) is 16.00 g/mol.
Substituting these values into the formula, we get:
Molar mass (Co(NO3)2) = 58.93 g/mol + 2 x 14.01 g/mol + 6 x 16.00 g/mol
Now, substitute the calculated value for moles and the molar mass into the formula for mass:
mass = moles x molar mass
Calculate the mass using the values we have discussed above.