Rectangle A and B are similar. The ratio of rectangle B's width to rectangle A's width is 3:2. Rectangle A has a length of 24 inches and a width of 16 inches. What is the perimeter of rectangle B?
perimeter of A = 2(24+16) = 80
Since perimeter is a linear measurement
x/80 = 3/2
2x = 240
x = 120
The perimeter of rectangle B is 120
check:
120:80 = 12:8 = 3:2
@Reiny
Thank you for answering that question actually, I already got the correct answer but my mind is not sure about it so I tried to ask but too late i passed my homework without the correct answer..hehe .. I forgot my password.. ^_^ lalalaah thanks again..
To find the perimeter of rectangle B, we first need to determine the dimensions of rectangle B. Since rectangles A and B are similar, the ratio of their widths is 3:2.
We can calculate the width of rectangle B by multiplying the width of rectangle A (16 inches) by the ratio of the widths:
16 inches * (3/2) = 24 inches
Now that we know the width of rectangle B is 24 inches, we can find its length by multiplying the length of rectangle A (24 inches) by the same ratio:
24 inches * (3/2) = 36 inches
Therefore, rectangle B has a length of 36 inches and a width of 24 inches.
To find the perimeter of rectangle B, we can use the formula:
Perimeter = 2 * (length + width)
Substituting the values, we have:
Perimeter = 2 * (36 inches + 24 inches)
Perimeter = 2 * (60 inches)
Perimeter = 120 inches
Therefore, the perimeter of rectangle B is 120 inches.