Chemistry

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Ca(OH)2 has a Ksp of 6.5 x 10^-6. If 0.37 g of Ca(OH)2 is added to 500 mL of water and the mixture is allowed to come to equilibrium, will the solution be saturated? pls help me I stayed up all last night trying to get this one question :(

  • Chemistry -

    ........Ca(OH)2 ==> Ca^2+ + 2OH^-
    I.......solid........0.......0
    C.......solid........x.......2x
    E.......solid........x.......2x

    Ksp = 6.5E-6 = (Ca^2+)(OH^-)^2
    6.5E-6 = (x)(2x)^2 = 4x^3
    Solve for x = [Ca(OH)2] in mols/L

    Convert that to grams/500 mL.
    g = mols x molar mass and that divided by 2 = g/500. Compare with the 0.37 g in the problem. If 0.37 g is larger than x the soln is not saturated. If 0.37 g is smaller it is saturated.

  • Chemistry -

    Thank you so much!

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