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What mass of Uranium (in mg) is contained in 1ml of 4.55M (UO2)3(PO4)3 solution?

How do I solve this?
*all numbers are subscripts

  • Chemistry -

    How many mols do you have? That's M x L = mols.
    There are 3 atoms U in 1 molecule of (UO2)3(PO4)3; therefore mols (UO2)3(PO4)3 x 3 = mols U
    g U = mols U x atomic mass U.
    Convert g to mg.

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