A man traveled a distance of 22km in one hour,partly in a car at a speed of 30km/hr and partly on a motorcycle at 18km/hr.find the distance travelled by him in the car.

Ans is 10km plz gve me fst sltn

This is right answer but this step is wrong .

To find the distance traveled by the man in the car, we need to set up an equation using the given information.

Let's assume the distance traveled in the car is 'x' km.

According to the problem, the total distance traveled is 22 km. So, the remaining distance traveled on the motorcycle would be (22 - x) km.

We also know that the man traveled for one hour, which means the sum of the times taken in the car and on the motorcycle is equal to one hour.

The time taken in the car can be calculated by dividing the distance traveled in the car by the speed of the car:
Time taken in the car = Distance traveled in the car / Speed of the car
= x / 30

Similarly, the time taken on the motorcycle can be calculated by dividing the distance traveled on the motorcycle by the speed of the motorcycle:
Time taken on the motorcycle = Distance traveled on the motorcycle / Speed of the motorcycle
= (22 - x) / 18

Since the total time taken is one hour, we can set up the equation:

Time taken in the car + Time taken on the motorcycle = 1

x / 30 + (22 - x) / 18 = 1

To solve this equation, we can multiply through by the least common multiple (LCM) of the denominators (30 and 18), which is 90, to get rid of the fractions:

90 * (x / 30) + 90 * ((22 - x) / 18) = 90

Canceling out the denominators, we get:

3x + 5(22 - x) = 90

Simplifying further:

3x + 110 - 5x = 90

-2x = -20

Solving for 'x', we have:

x = -20 / -2 = 10

Hence, the distance traveled by the man in the car is 10 km.

Therefore, the answer is 10 km.

if the distance traveled by car is c, the 22-c is on bike.

add up the times, knowing that time = distance/speed:

c/30 + (22-c)/18 = 1
clear fractions to get

3c + 5(22-c) = 90
3c + 110 - 5c = 90
2c = 20
c = 10

Thanx dear