Algebra 2..

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Solve for x.
2^4x-1/2^3x+2=4

  • Algebra 2.. -

    let z = 2^x, and you have

    z^4 - 1/z^2 + 2 = 4
    (z^6 - 1)/z^2 = 2

    don't like that. How about

    (z^4 - 1)/(z^3 + 2) = 4
    z^4 - 1 = 4z^3 + 8
    z^4 - 4z^3 - 9 = 0

    still no joy. You sure there's no typo somewhere?

    Ah. how about

    2^(4x-1) / 2^(3x+2) = 4
    since we're dividing, subtract exponents to get

    2^(x-3) = 4

    now, 4 = 2^2, so we have

    2^(x-3) = 2^2
    x-3 = 2
    x = 5

    See how important parentheses can be?

  • Algebra 2.. -

    Thank you.

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