A bus stopped at Gulgong, 25% of the passengers got off the bus and 3 new passengers got on. At the next stop,3 quarter of the passengers got off the bus and 11 new passengers got on. The bus then had 17 passengers.How many passengers did the bus have just before it stopped at Gulgong ?
X Passengers before stopping at Gulgong.
0.75x Remains.
0.75x+3.
0.25(0.75x+3)+11 = 17.
0.1875x + 0.75 = 17-11 = 6.
0.1875x = 5.25
X = 28.
To find out how many passengers the bus had just before it stopped at Gulgong, we need to work backwards from the given information.
Let's assume that the number of passengers before the bus stopped at Gulgong was "x".
According to the problem, 25% of the passengers got off the bus and 3 new passengers got on. This means that 0.25x passengers got off, and the new total became (x - 0.25x + 3) = (0.75x + 3).
Next, it says that at the next stop, three-quarters of the passengers got off the bus and 11 new passengers got on. This means that 0.75 * (0.75x + 3) passengers got off, and the new total became (0.25 * (0.75x + 3) + 11) = (0.1875x + 5.25 + 11) = (0.1875x + 16.25).
Finally, we are given that the bus had 17 passengers after all these changes. So we can set up the equation (0.1875x + 16.25) = 17 and solve for x.
0.1875x = 17 - 16.25
0.1875x = 0.75
x = 0.75 / 0.1875
x ≈ 4
Therefore, the bus had approximately 4 passengers just before it stopped at Gulgong.