Calculus
posted by Anonymous .
If f(x)=6arcsin(x4), find f'(x).

f' = 6/√(1x^8) * 4x^3 = 24x^3/√(1+x^8)
recall that f=6arcsin(x^4), so
sin(f/6) = x^4
1/6 cos(f/6) f' = 4x^3
f' = 24x^3/cos(f/6)
but cos(f/6) = √(1sin^2(f/6)) = √(1x^8)
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