Write a quadractic equation having given equations?

-9,9i

9i your welcome young solder

if you mean the given roots, you are out of luck if you want real coefficients.

If you have a typo and meant -9+9i, then the other root is -9-9i, so the quadratic is

(x-(-9+9i))(x-(-9-9i))
= ((x-9)+9i)((x-9)-9i)
= (x-9)^2 + 9^2
= x^2 - 18x + 162

To write a quadratic equation, let's first understand what the equation represents. A quadratic equation is a polynomial equation of degree two, which means it has at least one squared term. It is generally written in the form of ax^2 + bx + c = 0, where a, b, and c are constants.

Now, you have given two equations: -9 and 9i. Let's break down each equation and convert it into quadratic form.

1. Equation: -9
In this case, the equation is already in the quadratic form. We can write it as:
x^2 - 9 = 0

2. Equation: 9i
The term "i" indicates the imaginary unit, representing the square root of -1. Since i^2 = -1, we can incorporate this into our equation. Multiply both sides of the equation by -1 to isolate the imaginary term:
i = -9
-i^2 = 9
1 = 9
1 - 9 = 0

Combining both equations, we can write the quadratic equation as:
(x^2 - 9)(x^2 + 1 - 9) = 0

Simplifying the equation further:
(x^2 - 9)(x^2 - 8) = 0

So, the quadratic equation based on the given equations -9 and 9i is:
(x^2 - 9)(x^2 - 8) = 0