Chemistry

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At 22C(Celsius) an excess amount of a generic metal hydroxide M(OH)2 is mixed with pure water. The resulting equilibrium solution has a pH of 10.14. What is the Ksp of the salt at 22C? Help Please

  • Chemistry -

    ..........M(OH)2 ==> M^2+ + 2OH^-
    E.........solid......x.......2x
    pH = 10.14 pOH = 14-10.14 = 3.86
    pOH = -log(OH^-)
    Solve for OH^- = about 1.4E-4 but that's approximate. That means (M^2+) = 1/2 that.
    Ksp = (Mg^2+)(OH^-)^2
    Substitute and solve for Ksp.

  • Chemistry -

    Mr. DrBob222,

    would you mind explaining that a little more? I do not completely understand what is happening in the problem. Also, how do you know that Mg^2+ is half of OH^-?

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