Precalculus 2
posted by Greg .
Similiarly to a question I asked previously I took the same approach. the problem is:
what value(s) of theta solve the following equation? cos(theta)sin(theta)  2 cos(theta) = 0?
I let Cos theta = X and sin theta = X
unfortunately I end up with something completely odd. Can anyone help me out please?

Precalculus 2 
Reiny
cosØ sinØ  2cosØ = 0
factor it
cosØ(sinØ  2) = 0
cosØ = 0 > Ø = π/2 , 3π/2 (90°, 270°)
or
sinØ = 2 , which has no solution
so
Ø = π/2 or 3π/2
BTW, how can you let both cosØ and sinØ = x ???
that would be true only if cosØ = sinØ
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