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a steel ball rolls with a constant velocity across a tabletop 0.91 m high. it rolls off the table and hits the ground 0.77 m from the edge of the table. how fast was the ball rolling?

  • physics -

    The time it takes the ball to fall a distance h = 0.91 m is
    t = sqrt(2h/g) = 0.431 s
    The horizontal velocity component while rolling (and while falling) remains
    Vx = 0.77 m/0.431 s = 1.79 m/s

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