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use implicit differentiation to find dy/dx if x^3+y^3=6xy
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done
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use implicit differentiation to find dy/dx if x^3+y^3=6xy
Top answer:
3x^2 + 3y^2 dy/dx = 6x dy/dx + 6y dy/dx(3y^2 - 6x) = 6y - 3x^2 dy/dx = (6y - 3x^2)/(3y^2 - 6x) = (2y
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Alright so implicit differentiation is just not working out for me.
Use implicit differentiation to find the slope of the tangent
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It will be easier if you multiply it out and combine terms. 9y = x^4 +4x -2x^3 y Differentiate both
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I do not understand implicit differentiation. One of the problems are: find y' by implicit differentiation xy+2x+3x^2=4.
I would
Top answer:
Just differtiate each term with respect to x, remembering that y is a function of x. You often end
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I do not understand implicit differentiation. One of the problems are: find y' by implicit differentiation xy+2x+3x^2=4.
I would
Top answer:
if you can do the basic rules like the product rule, then you can do implicit differentiating.
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I just need the 3rd part!!!
(2 points) Let y be defined implicitly by the equation ln(2y)=5xy. Use implicit differentiation to
Top answer:
Well, you want the 2nd derivative = 0 so y^3(250xy-75)/((5xy-1)^3) = 0 y^3(250xy-75) = 0 y^3 = 0,
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Given y^4 -x^4=16 find and simplify d2y/dx2 using implicit differentiation.
I got the first derivative which was x^3/y^3 and no
Top answer:
y^4 - x^4 = 16 4y^3 y' - 4x^3 = 0 y' = x^3/y^3 y'' = (3x^2*y^3 - x^3*3y^2*y')/y^6 = 3x^2(y-xy')/y^4
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If cos(3 x)�6Ó14 x e^2 y=0, find [ dy/dx] using implicit differentiation.
In this problem, you should differentiate both sides
Top answer:
To find [dy/dx] using implicit differentiation, we first need to differentiate both sides of the
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How do you use imlicit differentiation to differentiate e^(xy)?
I have the problem "use implicit differentiation to find dy/dx.
Top answer:
e^(xy) + x^2 - y^2 = 10 e^(xy) (xdy/dx + y) + 2x - 2y dy/dx = 0 xe^(xy) dy/dx + ye^(xy) + 2x - 2y
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Find the derivative of the implicit function X^3+Y^3+6XY=0
Top answer:
To find the derivative of the implicit function x^3 + y^3 + 6xy = 0, we can use implicit
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find y'' by implicit differentiation.
2x^3 + 3y^3 = 8 I got the first derivative as you but the problem was asking for second
Top answer:
oops. Well, if you got y', y" is just a bit down the road There are two ways to do it. First, use y'
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use implicit differentiation to find dy/dx and then d^2y/dx^2
x^2/3 + y^2/3 = 1
(x-y)/(4x+3y)=6x find dy/dx by implicit differentiation.
find y'' by implicit differentiation.
2x^3 + 3y^3 = 8
