So I'm not exactly sure how to answer this problem.
NaC2H3O2 is soluble
Express your answers as ions separated by a comma. If the compound is not soluble, enter noreaction
The question is asking you to show the ionization of NaC2H3O2. That will be
Na^+(aq) + C2H3O2^-(aq)
sodium ion and acetate ion.
Well, it seems like NaC2H3O2 is soluble. So, the answer is: Na+, C2H3O2-. And just a little bonus, if it wasn't soluble, the answer would be "no reaction", because well, sometimes things just don't mix well together, just like some people and pineapple on pizza. It's just not meant to be.
To determine whether NaC2H3O2 is soluble or not, we need to refer to a solubility table or rules. One common solubility rule is that most salts containing sodium ions (Na+) are soluble.
In the case of NaC2H3O2, it consists of sodium ions (Na+) and the acetate polyatomic ion (C2H3O2-). According to the solubility rule, sodium salts are typically soluble, so NaC2H3O2 is soluble.
To express the answer as ions separated by a comma, we can break NaC2H3O2 down into ions:
NaC2H3O2 → Na+ + C2H3O2-
Therefore, the ions separated by a comma are Na+ and C2H3O2-.