Calculus

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Find an equation of the tangent line to the curve for the given value of t.

x=t^2-2t, y=t^2+2t when t=1

  • Calculus -

    dx/dt = 2t-2
    dy/dt = 2t+2

    when t=1
    slope = dy/dx = (dy/dt) / (dx/dt) = 4/0 , ahhh, a vertical line

    when t=1
    x = 1-2 = -1
    y = 1 + 2 = 3

    so a vertical line through (-1,2) is

    x = -1

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