calculus
posted by Martha .
Wiley jumps straight up in the air from the edge of a cliff so that when he comes down he falls off the cliff. The cliff is 40 feet off the ground. His height t seconds after he jumps is s= 16t2 + 12t + 40.What is the maximum height? What is his maximum velocity?

ds/dt = 32t + 12
= 0 for a max of s
32t = 12
t = 12/32 sec = 3/8 sec
for that time
s = 16(9/64) + 12(3/8) + 40
= 169/4 or 42.25 ft above the base of the cliff
when he hits the ground, s = 0
16t^2 + 12t +40=0
divide by 4
4t^2  3t  10 = 0
(t2)(4t+5) = 0
t = 2 or t = 5/4, but t > 0
so he will hit the ground after 2 seconds
ds/dt = 32t+12
when t=2
ds/dt = 32(2) + 12 = 52 ft/sec
the negative indicates a downward direction, he is falling
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