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Chemistry

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7 grams of chloride was dissolved in water. 20 ml of lead(II)nitrate was used to completely precipitate all chloride (assume atomic mass of 35g/mol). What is the molarity of the Lead(II) Nitrate solution.

  • Chemistry -

    2Cl^- + Pb^2+ ==> PbCl2

    mols Cl^- = grams/atomic mass Cl.
    mols PbCl2 = 1/2 that.
    mols Pb^2+ = mol PbCl2.
    mols Pb(NO3)2 = mols PbCl2.
    M Pb(NO3)2 = mols Pb(NO3)2/L soln.

  • Chemistry -

    DrBob222, Is the answer 5M?

  • Chemistry -

    Yes

  • Chemistry -

    thank you

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