Mikail used 220 inches of wire to make this figure.
The figure is made up of 2 indentical triangles, a 15 inch by 12 inch rectangle & a square of side 19 inches. What is the length of 1 side of each triangle if all the sides of the triangles are equal in length?
15 inches
15 inches
15
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The rectangle needs 2(15) + 2(12) or 54 inches
the square needs 4(19) or 6 inches.
So far we need 130 inches, leaving 90 for the 2 triangles.
For the two identical equilateral triangles we need 6 equal lengths or 90/6 or 15 inches for each side of the triangle
30+24=54 19x4=76+54=130 220-130=90/6=15 answer:15
15
15
To find the length of one side of each triangle, we need to first determine the total length of all the other components of the figure.
The figure is made up of two identical triangles, a rectangle, and a square. Let's calculate the total length of these components:
1. Each triangle has three equal sides, so the total length of the triangle's sides is 3 times the length of one side of the triangle.
2. The rectangle has two sides measuring 15 inches and two sides measuring 12 inches, giving us a total length of 2 times 15 inches plus 2 times 12 inches.
3. The square has four sides measuring 19 inches each, giving us a total length of 4 times 19 inches.
Now, we can write an equation that represents the total length of all the components:
3x + 2(15) + 2(12) + 4(19) = 220
Simplifying the equation, we have:
3x + 30 + 24 + 76 = 220
Combining like terms:
3x + 130 = 220
Subtracting 130 from both sides of the equation:
3x = 90
Dividing both sides by 3:
x = 30
Therefore, the length of one side of each triangle is 30 inches.