Calculus

posted by .

Consider an infinite series of the form

(+-)3(+-)1(+-)1/3(+-)1/9(+-)1/27(+-)....(+-)1/3^n(+-)...

The number 3,1, etc. are given but you will decide what the signs should be.
a)Can you choose the signs to make the series diverge?
B)Can you choose the signs to make the series sum to 3.5?
c)Can you choose the signs to make the series sum to 2.25?

In each case, if your answer is Yes, then specify how to choose the signs; if your answer is No, then explain

Respond to this Question

First Name
School Subject
Your Answer

Similar Questions

  1. algebra

    Can someone please help me with this problem?
  2. Calculus

    Infinite series question. an=2+(0.99)^n Converge or Diverge?
  3. Calculus

    Consider the infinite series of the form: (+/-)3(+/-)1(+/-)(1/3)(+/-)(1/9)(+/-)(1/27)(+/-)...(+/-)(1/3^n)(+/-)... (A) Find x and y from: x(</=)(+/-)3(+/-)1(+/-)(1/3)(+/-)...(</=)y. (B) Can you choose the signs to make the series …
  4. calculus

    Consider the infinite series of the form: (+/-)3(+/-)1(+/-)(1/3)(+/-)(1/9)(+/-)(1/27)(+/-)...(+/-)(1/3^n)(+/-)... (A) Find x and y from: x(</=)(+/-)3(+/-)1(+/-)(1/3)(+/-)...(</=)y. (B) Can you choose the signs to make the series …
  5. calculus

    Consider the infinite series of the form: (+/-)3(+/-)1(+/-)(1/3)(+/-)(1/9)(+/-)(1/27)(+/-)...(+/-)(1/3^n)(+/-)... (A) Find x and y from: x(</=)(+/-)3(+/-)1(+/-)(1/3)(+/-)...(</=)y. (B) Can you choose the signs to make the series …
  6. calculus

    Consider the infinite series of the form: (+/-)3(+/-)1(+/-)(1/3)(+/-)(1/9)(+/-)(1/27)(+/-)...(+/-)(1/3^n)(+/-)... (A) Find x and y from: x(</=)(+/-)3(+/-)1(+/-)(1/3)(+/-)...(</=)y.
  7. calculus

    Does the series from 0 to infinity of [1/square root of (n+4)] x cos(n x pi) converge or diverge?
  8. Calculus

    does infinite power series -1/n diverge? (i think so, because it is just the negative of the harmonic series)...?
  9. Pre-Calculus

    Q.Determine the sum of each infinite geometric series. t_1= 8 r = -2^1/2 ---------------------------------------- A.This is a divergent series because the absolute value of r is greater than 1. ---------------------------------------- …
  10. Algebra 2

    I need steps on how to complete this please i am so confused and lost. :( Consider the infinite geometric series x e n=1 -4(1/3) n-1. In this image, the lower limit of the summation notation is "n=1". a. Write the first four terms …

More Similar Questions