Precalculus
posted by Mary
The question(s) are as follows:
Given: f(x) = 3cos(3x+π)  4
Find:
a) the inverse of F(x)
b) the domain and range of F(x)
c) the domain and range of F 1(x)
I got cos1[(x4)/9]  π = y for the inverse, although I'm not sure I did the problem right (I set x to y and y to x and then solved for y).
For the domain of F1(x) I got [5,5] and for the range I got [π/3,1 π/3]
Is this right?
For cos(3x+π) = 4/3, don't I have to finish solving cos(3x+π) before I decide that there is no solution (Since 4/3 isn't between 1 and 1)? I have been doing these and other problems for so long today that I am getting more confused  not less, lol! Thanks for your help.
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