A crate of mass 80 kg stands on level ground. A worker exerts a horizontal force of 120 N on the crate. If the coefficient of friction between the crate and the ground is 0.25, and F N is the magnitude of the frictional
Incomplete.
To find the magnitude of the frictional force (F_N), we can use the equation:
F_N = coefficient of friction * Normal force
First, we need to find the Normal force (N). The Normal force is the force exerted by a surface to support the weight of an object resting on it. In this case, the Normal force is equal to the gravitational force acting on the crate, since the crate is on level ground. The equation for gravitational force is:
F_gravity = mass * acceleration due to gravity
Where the mass of the crate is 80 kg and the acceleration due to gravity is approximately 9.8 m/s^2. So, the gravitational force is calculated as:
F_gravity = 80 kg * 9.8 m/s^2 = 784 N
Since the Normal force is equal to the gravitational force in this case, N = F_gravity = 784 N.
Now, we can find the magnitude of the frictional force (F_N) using the given coefficient of friction of 0.25:
F_N = 0.25 * 784 N = 196 N
Therefore, the magnitude of the frictional force (F_N) is 196 N.