# Algebra

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An apple orchard charges a fixed amount for the first four bushels of apples purchased and an extra amount for each additional bushel purchased. If the cost of 11 bushels of apples is \$33 and the cost of 19 bushels is \$55, what is the fixed charge for the first four bushels of apples?

• Algebra -

fc + (11-4)*b = fc + 7*b = 33

fc + (19-4)*b = fc + 15*b = 55

where fc is the fixed charge of the first 4 bushels, and b is the price per bushel of each additional bushel over 4

Use algebra to solve these two equations for b and fc:

fc + 7*b = 33
fc + 15*b = 55

• Algebra -

let
cost = m(n-4) + b , where n is the number of bushels, b is the extra charge for the first 4 bushels and m is the cost per bushel
so for 11 bushels, cost is 33
33 = 7m + b
so for 19 bushels, cost = 55
55 = 15m + b
subtract them
22 = 8m
m = 22/8 = 2.75
sub into 33 = 7m+b
33 = 19.25 + b
b = 13.75

the fixed cost is \$13.75

check:
our equation would be
cost = 2.75(n-4) + 13.75

if n = 11, cost = 2.75(7) + 13.75 = 33
if n=19, cost = 2.75(15) + 13.75 = 55 , YEAH

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