a school is 800 m from the base of a cellphone tower.if the angle of elevation of the tower is 45 degree 45 inches from the school,how high is the tower?
801.14
looks like
height/800 = tan 45°
height = 800(1) = 800
813.72 meters
To find the height of the tower, we need to use trigonometry and the angle of elevation.
First, draw a diagram to visualize the situation. Place the school at a point on the ground, and draw a line connecting it to the top of the tower. This line represents the hypotenuse of a right triangle. The base of the triangle is the distance from the school to the tower, which is given as 800 m. The angle of elevation is the angle between the hypotenuse and the horizontal ground.
Next, we can use the tangent function, which relates the opposite side (height of the tower) to the adjacent side (distance from the school to the tower).
tan(angle of elevation) = height of tower / distance from school to tower
In this case, the angle of elevation is given as 45 degrees and 45 inches (you might want to clarify if that's the correct information, as it's unusual to mix degrees and inches in the same context). Assuming it should be 45 degrees, the equation becomes:
tan(45°) = height of tower / 800 m
The tangent of 45 degrees is equal to 1, so we can simplify the equation:
1 = height of tower / 800 m
To find the height of the tower, we can rearrange the equation:
height of tower = 1 * 800 m
Therefore, the height of the tower is 800 meters.