Is this correct? If one card is drawn from a regular deck of cards,what is the probability the card will not be an ace? 1/13 is the probability
The probability it WILL be an ace = 1/13. The probability it will NOT be an ace = 1 - 1/13 = ?
No, 1/13 is not correct. There is a 12/13 probability that the drawn card is NOT an ace.
Alex , I had answered your question before you reposted it
http://www.jiskha.com/display.cgi?id=1352503674
By not checking your old posting you are causing other tutors to do unnecessary and extra work.
Yes, that is correct. The probability that a randomly drawn card from a regular deck of cards is not an ace is indeed 1/13.
To explain how to arrive at this answer, let's break down the problem:
1. We have a standard deck of 52 cards, which consists of four suits (hearts, diamonds, clubs, and spades) and each suit has 13 cards (Ace, 2-10, Jack, Queen, and King).
2. There are a total of 4 aces in the deck, one for each suit.
3. Since we want to find the probability that the drawn card is not an ace, we need to determine the number of cards that are not aces. This would be 52 (total cards in the deck) minus 4 (number of aces), which equals 48.
4. Finally, we divide this value (48) by the total number of possible outcomes (52) to get the probability. Thus, the probability would be 48/52, which simplifies to 12/13.
So, the probability that the card drawn will not be an ace is 12/13 or approximately 0.9231.