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A file cabinet weighing 1500 N is at rest on the floor. The coefficient of static friction between the floor and the cabinet is 0.5. What is the minimum force required to make the file cabinet move horizontally

  • Physics -

    Fc = 1500 N @ 0o. = Force of cabinet.
    Fp = 150*sin(0) = 0 = Force parallel to floor.
    Fv = 1500*cos(0) = 1500 N. = Force perpendicular to floor = Normal.

    Fs = u*Fv = 0.5*1500 = 750 N. = Force of
    static friction.

    Fap-Fp-Fs = m*a.
    Fap-0-750 = m*0 = 0
    Fap = 750 N. = Force applied.

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