write the function whose grapg is the graph of y=(x+5)^2, but is reflected about the y-axis.
would it look like this: y=(x+5)-2??
Nope. Replace x by -x:
y = (-x+5)^2
y = (x-5)^2
The vertex moves from x = -5 to x = +5
Thnaks Steve!!
To reflect the graph of y = (x + 5)^2 about the y-axis, you need to negate the x-values. This means that each x-value will be multiplied by -1. Therefore, the reflected function would be:
f(x) = (-x + 5)^2
So, the correct function would be:
y = (-x + 5)^2
To reflect a function about the y-axis, you need to replace every occurrence of x with its negation, -x.
The given function is y = (x + 5)^2.
To reflect it about the y-axis, you need to replace x with -x:
y = (-x + 5)^2
So, the function whose graph is the reflection of y = (x + 5)^2 about the y-axis is y = (-x + 5)^2.