A pump slowly lifts 3.0*10^6 kg of water an average distance of 80.0m in 12minutes. 1) how much work is done in the first 12 minutes? 2)How much power is delivered by the pumps?
F = 3*10^6kg * 9.8N/kg = 2.94*10^7 N.
1. Work = F*d = 2.94*10^7*80=2.352*10^9
Joules.
2. P = W/T = 2.352*10^9 / 720s. = 3.27*10^6 Joules/s. = 3.27*10^6 Watts.