Calculus
posted by Ashley .
A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. The total volume of the solid is 2 cubic centimeters. Find the radius of the cylinder that produces the minimum surface area. (Round your answer to three decimal places.)

if the cylinder is of radius r and height h, the volume v is
v = 4/3 pi r^3 + pi r^2 h
so, h = (v  4/3 pi r^3)/(pi r^2)
h = (2  4/3 pi r^3)/(pi r^2)
the surface area a is
a = 4pi r^2 + 2pi r h
= 4pi r^2 + 2pi r (2  4/3 pi r^3)/(pi r^2)
= 4pi r^2 + 2/r (2  4/3 pi r^3)
= 4pi r^2 + 4/r  8pi/3 r^2
= (4pi  8pi/3) r^2 + 4/r
= 4pi/3 r^2 + 4/r
maximum area where da/dr = 0
da/dr = 8pi/3 r  4/r^2
= (8pi/3 r^3  4)/r^2
da/dr=0 when r = ∛(3/2π)
As usual, check my math to verify result. 
Is pi in the denominator?

yes.

what is r?