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algebra

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joe has a collection of nickles and dimes that is worth $6.10. If the number of dimes was tripled and the number of nickles was increased by 49, the value of coins would be $18.95.how many nickles and dimes does he have?

  • algebra -

    5n + 10d = 610
    5(n+49) + 10(3d) = 1895

    n=18,d=52

    check:
    18 nickels = 0.90
    52 dimes = 5.20
    sum = 6.10

    67 nickels = 3.35
    156 dimes = 15.60
    sum = 18.95

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