A hailstone traveling with a velocity of 43 meters/second comes to a virtual stop 0.28 seconds after hitting water. What is the magnitude of its acceleration in the water?
-43 m/s /.28 s = -153.5 m/s^2
A hailstone traveling with a velocity of 43 meters/second comes to a virtual stop 0.28 seconds after hitting water. What is the magnitude of its acceleration in the water?
A hailstone traveling with a velocity of 43 meters/second comes to a virtual stop 0.28 seconds after hitting water. What is the magnitude of its acceleration in the water?
Expand Dong
To find the magnitude of the hailstone's acceleration in the water, we can use the formula:
acceleration = (change in velocity) / (time taken)
In this case, the change in velocity is the final velocity of the hailstone when it comes to a stop, minus its initial velocity.
Given:
Initial velocity (u) = 43 m/s
Final velocity (v) = 0 m/s
Time taken (t) = 0.28 seconds
The change in velocity is:
change in velocity = final velocity - initial velocity
= 0 m/s - 43 m/s
= -43 m/s (Note: negative sign indicates the change is in the opposite direction of initial velocity)
Now, we can plug the values into the formula to find the magnitude of acceleration:
acceleration = change in velocity / time taken
= -43 m/s / 0.28 s
≈ -153.57 m/s^2
The magnitude of the hailstone's acceleration in the water is approximately 153.57 m/s².