A small sphere of mass m = 7.50 g and charge

q1 = 32.0 nC is attached to the end of a string and hangs vertically as shown in
the figure. A second charge of equal mass and charge q2 = –58.0 nC is located a
distance d = 2.00 cm below the first charge.
(a) Find the tension in the string.
(b) If the string can withstand a maximum tension of 0.180 N, what is the
smallest value d can have before the string breaks?

(a) T= m1•g + F(el)= m1•g+ k•q1•q2/r²=

=7.5•10⁻³•9.8 + 9•10⁹•32•10⁻⁹•58•10⁻⁹/0.02²=…
(b) T1= m1•g + F(el)= m1•g+ k•q1•q2/r1²=
T1=0.18 N. Solve for r1

Please i need question and answers

A charged particle A exerts a force of 2.62 N to the right on charged particle B when the particles are

13.7 mm apart. Particle B moves straight away from A to make the distance between them 17.7 mm.
What vector force does particle B then exert on A?
ans : 1.57 N directed to the left

To find the tension in the string, we need to consider the forces acting on the small sphere:

1. Gravitational force (Fg): The weight of the sphere acts downward and is given by the formula Fg = mg, where m is the mass of the sphere and g is the acceleration due to gravity.

2. Electromagnetic force (Fe): The force between the two charges can be found using Coulomb's law. The formula for the electromagnetic force is Fe = k * q1 * q2 / r^2, where k is the electrostatic constant, q1 and q2 are the charges of the two spheres, and r is the distance between them.

(a) To find the tension in the string, we need to set up the equilibrium condition where the net force is zero. In this case, the gravitational force and the electromagnetic force need to balance each other out. Therefore, we have:

Tension = Fg + Fe

Substituting the formulas for Fg and Fe, we get:

Tension = mg + k * q1 * q2 / r^2

Plugging in the values given in the problem (m = 7.50 g, q1 = 32.0 nC, q2 = -58.0 nC, r = 2.00 cm, and g = 9.8 m/s^2), we can calculate the tension.

(b) To find the smallest value of d before the string breaks, we need to consider the maximum tension the string can withstand. In this case, the maximum tension is given as 0.180 N. So we set up the equation:

Tension = 0.180 N

By rearranging the equation and substituting the formula for tension, we can solve for the smallest value of d.