In a skating stunt known as crack-the-whip, a number of skaters hold hands and form a straight line. They try to skate so that the line rotates about the skater at one end, who acts as the pivot. The skater farthest out has a mass of 80.0 kg and is 5.35 m from the pivot. He is skating at a speed of 6.15 m/s. Determine the magnitude of the centripetal force that acts on him.
1 N
Well, if we're talking about skating stunts involving cracks and whips, I guess we're getting into some extreme skateboarding here. Let's calculate that centripetal force and keep things rolling!
To find the magnitude of the centripetal force, we can use the formula:
F = (m * v^2) / r
Where:
F is the centripetal force
m is the mass of the skater
v is the speed of the skater
r is the distance from the pivot
Plugging in the values we have:
m = 80.0 kg
v = 6.15 m/s
r = 5.35 m
F = (80.0 kg * (6.15 m/s)^2) / 5.35 m
Calculating that, we get:
F ≈ 446.84 N
So, the magnitude of the centripetal force acting on the skater at the end of the line is approximately 446.84 N.
Keep those skate tricks up! Just remember to crack some jokes while you're at it!
To determine the magnitude of the centripetal force that acts on the skater, you can use the equation:
Centripetal Force = (mass x velocity^2) / radius
Given:
Mass (m) = 80.0 kg
Velocity (v) = 6.15 m/s
Radius (r) = 5.35 m
Substituting these values into the equation, we get:
Centripetal Force = (80.0 kg x (6.15 m/s)^2) / 5.35 m
Calculating this expression, we find:
Centripetal Force = (80.0 kg x 37.8225 m^2/s^2) / 5.35 m
Centripetal Force = 3017.8 kg m/s^2 / 5.35 m
Centripetal Force = 563.18 N
Therefore, the magnitude of the centripetal force that acts on the skater is approximately 563.18 N.
To determine the magnitude of the centripetal force acting on the skater farthest out in the crack-the-whip stunt, we can use the formula:
F = (mv^2) / r
Where:
- F is the force (centripetal force)
- m is the mass of the skater (80.0 kg)
- v is the speed of the skater (6.15 m/s)
- r is the distance from the pivot point (5.35 m)
Now, let's substitute these values into the formula:
F = (80.0 kg) * (6.15 m/s)^2 / 5.35 m
F = (80.0 kg) * (37.8225 m^2/s^2) / 5.35 m
F ≈ 570.15 N
Therefore, the magnitude of the centripetal force acting on the skater farthest out is approximately 570.15 N.