Physics
posted by Donald .
In the figure below, an object, after being released from its circular path, travels the distance OA in the same time it would have moved from O to P on the circle. The speed of the object on and off the circle remains constant at the same value. Suppose that the radius of the circle in the figure below is 3.6 m and the angle è is 29°. What is the distance OA?
1 m

θ=29°=0.5 rad
The angular displacement θ=ω•t=(v/R) •t => t=θ•R/v
OA=v•t=v• θ•R/v= θ•R=0.5•3.6=1.8 m
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