Physics

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A 15 kg uniform ladder leans againt a wall in the atrium of a large hotel. The ladder is 8m long, and it makes an angle as 60 degree with the floor. The coefficient of static friction between the floor and the ladder is u+ 0.45. Assume the wall is frictionless.

a) How far along the ladder can a 60kg painter climb before the ladder starts to slip?

b) Therefore, at where height above the ground can the same painter climb before the ladder starts to slip ?

  • Physics -

    I am going to say g = 10 m/s^2
    base of ladder from wall = 4 m
    top of ladder at 4 sqrt 3 = 6.93 m
    Take moments about top point of ladder
    total weight = 10 (15+60) = 750 N
    Friction force = .45*750 = 338 N
    Clockwise:
    750 N * 4 m = 3000
    Counterclockwise:
    x is horizontal distance painter to wall
    338*6.93 + 150*2 + 600(x)
    so
    600 x = 3000 - 2342 - 300 = 358
    x = .596 m
    along ladder to top = 2x = 1.19 m
    so along ladder from bottom = 8 -1.19 = 6.8 m from floor along ladder to painter
    height of painter = (6.8)/2 sqrt 3 = 5.9 m

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