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A 50 kg diver leaps off the 20 meter diving board with a velocity of 5 m/s. What is his kinetic energy just before hitting the water?

  • physics -

    What is direction of initial velocity?
    If v=5 m/s is downward velocity,
    mgh+mv1²/2 =mv2²/2
    v2 =sqrt(2gh+v1²)

  • physics -

    F=50(5)= 250

    M(k)=250/(50(9.8))= .51 is the coefficent of his kinetic energy while 250 is his kinetic force.

    Probably wrong but that's how I would have done it

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