One day we decidid to drive from town A to town D.In order to get there,we had to drive through town B and C.It is ten miles farther from town A to town B than it is from town B to town C.It is ten miles farther from town B to town C than it is from town C to town D. It is 330 miles from town A to town D.How far is it from town A to town B?

Start with this: c to d is x, b to c is x+10, and a to b is x +10+10

To find the distance from town A to town B, we can follow a step-by-step approach.

Step 1: Assign variables
Let's assume:
- The distance from town A to town B as x
- The distance from town B to town C as y
- The distance from town C to town D as z

Step 2: Set up equations
From the given information, we know:
- It is ten miles farther from town A to town B than it is from town B to town C. This can be written as: x = y + 10
- It is ten miles farther from town B to town C than it is from town C to town D. This can be written as: y = z + 10
- It is 330 miles from town A to town D. This can be written as: x + y + z = 330

Step 3: Solve the equations

Let's substitute equation (2) into equation (1):
x = (z + 10) + 10
x = z + 20

Now substitute equation (2) and (3) into equation (1):
(z + 20) + z + 10 + z = 330
3z + 30 = 330
3z = 330 - 30
3z = 300
z = 100

Substitute the value of z in equation (2):
y = z + 10
y = 100 + 10
y = 110

Substitute the value of z in equation (1):
x = z + 20
x = 100 + 20
x = 120

Therefore, it is 120 miles from town A to town B.