A 2000 kg truck is at rest at a stop sign. A 1100kg car collides head-on with the truck. The car was moving at 15.0m/s before the collision if the collision was completely inelastic, what is the velocity of the car and the truck after the collision?
m1•0+m2•v2=(m1+m2)v
v=m2•v2/(m1+m2)
100000
To find the velocities of the car and the truck after the collision, we need to apply the principle of conservation of momentum.
The principle of conservation of momentum states that the total momentum of an isolated system remains constant before and after a collision. In this case, the car and the truck can be considered as an isolated system because no external forces are acting on them during the collision.
The equation that represents conservation of momentum is:
(m1 * v1) + (m2 * v2) = (m1 + m2) * Vf
Where:
m1 and m2 are the masses of the car and the truck, respectively.
v1 and v2 are the initial velocities of the car and the truck, respectively.
Vf is the final velocity of both objects after the collision.
Given:
m1 = 1100 kg (mass of the car)
v1 = 15.0 m/s (initial velocity of the car)
m2 = 2000 kg (mass of the truck)
v2 = 0 m/s (initial velocity of the truck)
Substituting the given values into the conservation of momentum equation, we get:
(1100 kg * 15.0 m/s) + (2000 kg * 0 m/s) = (1100 kg + 2000 kg) * Vf
16500 kg·m/s = 3100 kg * Vf
Divide both sides of the equation by 3100 kg to solve for Vf:
16500 kg·m/s / 3100 kg = Vf
Vf ≈ 5.32 m/s
Therefore, the velocity of both the car and the truck after the completely inelastic collision is approximately 5.32 m/s.