Find the area between the following functions

2y=2x^2; y=1-x^2 & x=1

the curves intersect at (1/√2,1/2)

a = integral[1/√2,1] x^2 - (1-x^2) dx
= 1/3 (√2-1)

seems reasonable, since the region is basically a triangle of base 1, height 1 - 1/√2, with area 1/2√2 (√2-1)