calculus
posted by Alex .
Given: y^2+h^2=1
Find h as a function of y. If expression for dy/dx includes h, substitute the expression in terms of y for h. Write dy/dx in terms of y only.
Show that x=[(1+sqrt(1y^2))/y]sqrt(1y^2) satisfies the differential equation you found to prove this equation generates the curve.
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