In a physics laboratory experiment, a coil with 170 turns enclosing an area of 10cm^2 is rotated from a position where its plane is perpendicular to the earth's magnetic field to one where its plane is parallel to the field. The rotation takes 5.0×10^2 s . The earth's magnetic field at the location of the laboratory is 6.0×10?5T . please explain angles chosen.. I thought for the first part we are suppose to use cos (90) and for the second one cos (0) A) What is the total magnetic flux through the coil before it is rotated? b) What is the total magnetic flux through the coil after it is rotated?
Pease restate the Earth's magnetic field. Why is there a ? where there should be a ^ ? Shouldn't there be a minus sign?
The magnetic flux before the coil is rotated is
B*A*N
where N is the number of turns.
A = 10^-3 m^2
To find the total magnetic flux through the coil before and after rotation, we need to use the equation:
Φ = B * A * cos(θ)
Where:
Φ is the magnetic flux
B is the magnetic field strength
A is the area of the coil
θ is the angle between the magnetic field and the normal to the plane of the coil
Let's calculate the total magnetic flux before rotation (Φ1):
Given:
B = 6.0×10^(-5) T (Earth's magnetic field)
A = 10 cm^2 (area of the coil)
To find θ for the first part of the experiment (perpendicular to the Earth's magnetic field), we use cos(90°). So, θ1 = 90°.
Now, let's calculate Φ1:
Φ1 = B * A * cos(θ1)
= (6.0×10^(-5) T) * (10 cm^2) * cos(90°)
= 6.0×10^(-5) * 10 * 0
= 0
Therefore, the total magnetic flux through the coil before rotation (Φ1) is zero because the coil is perpendicular to the Earth's magnetic field.
Moving on to the second part of the experiment where the coil is rotated to a position parallel to the magnetic field:
Given:
B = 6.0×10^(-5) T (Earth's magnetic field)
A = 10 cm^2 (area of the coil)
To find θ for the second part (parallel to the Earth's magnetic field), we use cos(0°). So, θ2 = 0°.
Now, let's calculate Φ2:
Φ2 = B * A * cos(θ2)
= (6.0×10^(-5) T) * (10 cm^2) * cos(0°)
= 6.0×10^(-5) * 10 * 1
= 6.0×10^(-4) T·cm^2
Therefore, the total magnetic flux through the coil after rotation (Φ2) is 6.0×10^(-4) T·cm^2.