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college algebra

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graph the following function using transformations, be sure to graph all of the stages on one grph, state the domain and range y= x^2 +12x

  • college algebra -

    y = x(x+12)
    so the x-intercepts are 0 and -12
    and the x of the vertex must be halfway between those intercepts
    x of vertex is -6
    then y = 36 - 6(12) = -36

    vertex is ((-6,-36), opens up, and has x-intercepts of 0 and -12

    domain: obviously any value of x
    range: y ≥-36

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