Show the steps necessary to transform the compound on the left into the acid on the right
(CH3)3CCH2BR ------------------>(CH3)3CCH2C(=O)OH
To transform the compound on the left, (CH3)3CCH2BR, into the acid on the right, (CH3)3CCH2C(=O)OH, the following steps are needed:
Step 1: Remove the halogen atom (BR)
The compound on the left consists of an alkyl halide with a bromine (Br) atom. The first step is to remove this halogen atom to create a new carbon-carbon bond.
Step 2: Form a double bond with oxygen (O)
In the acid on the right, there is a double bond between carbon (C) and oxygen (O). To transform the alkyl halide into an acid, we need to convert the carbon next to the eliminated bromine atom into a carbonyl group, which includes a double bond with oxygen.
Step 3: Oxidize the carbon next to the bromine atom
To form the carbonyl group, we need to oxidize the carbon atom next to the bromine atom. A common method for this oxidation is to use an oxidizing agent like potassium permanganate (KMnO4) or chromium trioxide (CrO3) with an acidic medium.
Step 4: Remove the proton from the hydroxyl group (OH)
Finally, remove the proton (H+) from the hydroxyl group (OH) that forms after the oxidation step. It will result in the formation of an acid, indicated by the presence of the carbonyl group and the acidic functional group (OH).
Please note that the specific reaction conditions and reagents may vary depending on the methodology chosen. It is essential to consult relevant literature or a trusted source to determine the most suitable approach for this transformation.