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A hardware supplier manufactures three kinds of fasteners, type A,B and C. Production restrictions require it to make 10 units more of type C than the total of the other types and twice as many type B as type A. The shop must produce a total of 490 units per day. How many units of each type can be made per day.

  • math -

    C = A+B+10
    B = 2A
    A+B+C = 490

    A=80
    B=160
    C=250

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