PHYSICS HELP!
posted by Shelby .
A typical propeller of a turbine used to generate electricity from the wind consists of three blades as in the figure below. Each blade has a length of L = 33 m and a mass of m = 415 kg. The propeller rotates at the rate of 21 rev/min. 120degree angle between blades
a) Convert the angular speed of the propeller to units of rad/s.
(b) Find the moment of inertia of the propeller about the axis of rotation.___J ยท s2
(c) Find the total kinetic energy of the propeller.______ J

This is pretty standard question. What is it you do not understand?
For the moment of inertial figure each blade rotating about its end, then multiply by three.
KE=1/2 Itotal*w^2 
(A) w = (21rev/min) * (1min/60sec) * (2pi rad/1rev) = 2.2 rad/s
(B)
I = MR^2
I = (415kg)(33m)^2
I = 4.52E5 (I for one propeller)
I for all three propellers = (4.52E5) * 3 = 1.36E6
(C) KE = (1/2) * Iw^2
= (1/2)(4.52E5)(2.2)^2
=1.1E6 J
The book gives solutions for I and KE using one propeller. My thought were to multiply I *3....a little confusing. Thoughts...?
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