A dock is 7 3/4m high. The portion of the dock above water one day was measured at 2 2/5 m high. How much of the dock structure was below water that day?
7.75 - 2.4 = ?
To find out the portion of the dock structure that was below water, we need to subtract the portion above water from the total height of the dock.
Step 1: Convert the total height of the dock and the portion above water to fractions.
Total height of the dock = 7 3/4 = 7 + 3/4 = 28/4 + 3/4 = 31/4
Portion of the dock above water = 2 2/5 = 2 + 2/5 = 10/5 + 2/5 = 12/5
Step 2: Subtract the portion above water from the total height of the dock.
31/4 - 12/5
Step 3: To subtract fractions with different denominators, we need to find a common denominator.
The least common multiple (LCM) of 4 and 5 is 20.
Step 4: Convert the fractions to have a denominator of 20.
31/4 = (31/4) * (5/5) = 155/20
12/5 = (12/5) * (4/4) = 48/20
Step 5: Subtract the fractions.
155/20 - 48/20 = (155 - 48)/20 = 107/20
Therefore, on that day, 107/20 of the dock structure was below water.
To find out how much of the dock structure was below water that day, we can subtract the portion of the dock above water from the total height of the dock.
The total height of the dock is 7 3/4 meters.
The portion of the dock above water is 2 2/5 meters.
To solve this, we need to convert the mixed numbers to improper fractions:
Total height of the dock: 7 3/4
= (7 * 4 + 3) / 4
= 31/4 meters
Portion of the dock above water: 2 2/5
= (2 * 5 + 2) / 5
= 12/5 meters
Now, we can subtract the portion of the dock above water from the total height of the dock:
31/4 - 12/5
To subtract fractions, we need to find a common denominator, which is the least common multiple (LCM) of the denominators, which in this case is 20.
Converting the fractions to have the common denominator of 20:
(31/4) * (5/5) = 155/20
(12/5) * (4/4) = 48/20
Now, we can subtract the fractions:
(155/20) - (48/20) = 107/20
Therefore, the portion of the dock structure below water that day was 107/20 meters.
We can also convert this fraction to a mixed number:
107/20 = 5 7/20 meters
Therefore, the portion of the dock structure below water that day was approximately 5 7/20 meters.