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An object of mass 26 kg is thrown straight upwards from the ground at 27 m/s. Due to air resistance (a non-conservative force), the object loses some of its initial energy during its trip to reach maximum height and only travels to a height above the ground of 16.3 meters. What percentage of its initial energy is lost to air resistance during its flight to maximum height?

  • physics -

    Without air resistance
    KE=PE
    mv²/2=mgh
    h=v²/2g =27²/2•9.8 = 37.2 m
    (mgh-mgh1)/mgh = (h-h1)/h= (37.2-16.3)/37.2=0.56
    56%

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