Algebra I

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How do you make an equation that's perpendicular to the equation y=x+5? The given points are (3,-3)

Please help and explain step by step thank you!

  • Algebra I -

    slopes of perpendicular lines multiply to give -1.

    slope of y=x+5 is 1
    slope of perpendicular line is thus -1

    so, you want a line with slope -1 through (3,-3).

    Pull out your point-slope form of the line:

    y+3 = -1(x-3)
    y = -x

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